网站介绍:文章浏览阅读818次。帮同事处理List[scala.collection.immutable.Map[String,Any]]的排序问题原来想的办法是var x = mylist.sortWith(_.get("commonCount").toString > _.get("commonCount").toString)_.get("commonCount")可以取出值,但类型是Some,要..._scala immutable.map
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