JS获取URL参数和ajax请求_js中ajax地址不通怎么获取-CSDN博客

网站介绍:文章浏览阅读316次。// 获取url参数function getUrlVars() { var vars = {}; var parts = decodeURI(window.location.href).replace(/[?&]+([^=&]+)=([^&#]*)/gi, function(m,key,value) { vars[key] = value; } ); return vars;}var data = getUrlVars()// 浏览器不刷新时执行if_js中ajax地址不通怎么获取